What is log_{2}((c\sqrt[3]{d})/(e^4)) ?

The solution to log_{2}((c\sqrt[3]{d})/(e^4)) is log_{2}(c)+log_{2}(\sqrt[3]{d})-4log_{2}(e)

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simplify log_{2}((c\sqrt[3]{d})/(e^4))

simplify

Solution steps

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{2} (e^{4}) = 4 lo g_{2} (e)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

3 ln (3) + 3 ln (y)

lo g_{b} (y^{5} z)

lo g_{3} (m) + lo g_{3} (5) - lo g_{3} (n)

\frac{1}{lo g _{2} ( 10 ) + lo g _{2} ( 9 )}

lo g_{9} (8) - lo g_{9} (11)

What is log_{2}((c\sqrt[3]{d})/(e^4)) ?
The solution to log_{2}((c\sqrt[3]{d})/(e^4)) is log_{2}(c)+log_{2}(\sqrt[3]{d})-4log_{2}(e)