What is log_{10}(27)-log_{10}(9) ?

The solution to log_{10}(27)-log_{10}(9) is log_{10}(3)

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simplify log_{10}(27)-log_{10}(9)

simplify

lo g_{10} (27) - lo g_{10} (9)

lo g_{10} (3)

Decimal Notation

0.47712 \dots

Solution steps

lo g_{10} (27) - lo g_{10} (9)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (27) - lo g_{10} (9) = lo g_{10} (\frac{27}{9})

= lo g_{10} (\frac{27}{9})

Divide the numbers:

\frac{27}{9} = 3

= lo g_{10} (3)

2 lo g_{10} (3) - 3 lo g_{10} (2)

ln (5) + ln (2)

1 - lo g_{4} (m - 1) - lo g_{4} (m + 1)

lo g_{2} (3) - 3 lo g_{2} (x) + \frac{1}{2} lo g_{2} (x + 1)

ln (\frac{x + y}{x - y})

What is log_{10}(27)-log_{10}(9) ?
The solution to log_{10}(27)-log_{10}(9) is log_{10}(3)