What is x^2+x+1-2log_{10}(x)+3log_{10}(x+1) ?

The solution to x^2+x+1-2log_{10}(x)+3log_{10}(x+1) is x^2+x+1+log_{10}(((x+1)^3)/(x^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify x^2+x+1-2log_{10}(x)+3log_{10}(x+1)

simplify

x^{2} + x + 1 - 2 lo g_{10} (x) + 3 lo g_{10} (x + 1)

x^{2} + x + 1 + lo g_{10} (\frac{( x + 1 ) ^{3}}{x ^{2}})

Solution steps

x^{2} + x + 1 - 2 lo g_{10} (x) + 3 lo g_{10} (x + 1)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x) = lo g_{10} (x^{2})

= x^{2} + x + 1 - lo g_{10} (x^{2}) + 3 lo g_{10} (x + 1)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{10} (x + 1) = lo g_{10} ((x + 1)^{3})

= x^{2} + x + 1 - lo g_{10} (x^{2}) + lo g_{10} ((x + 1)^{3})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} ((x + 1)^{3}) - lo g_{10} (x^{2}) = lo g_{10} (\frac{( x + 1 ) ^{3}}{x ^{2}})

= x^{2} + x + 1 + lo g_{10} (\frac{( x + 1 ) ^{3}}{x ^{2}})

10 lo g_{10} (\frac{s}{1 0 ^{- 12}})

ln (\frac{22}{3})

- lo g_{10} (4.2 \cdot 1 0^{- 3})

lo g_{2} (6) - 6 lo g_{2} (x) + \frac{1}{2} lo g_{2} (x + 1)

5 lo g_{4} (\frac{a ^{2} b}{n ^{3}})

What is x^2+x+1-2log_{10}(x)+3log_{10}(x+1) ?
The solution to x^2+x+1-2log_{10}(x)+3log_{10}(x+1) is x^2+x+1+log_{10}(((x+1)^3)/(x^2))