What are the solutions to the equation x^2-72=12x ?

The solutions to the equation x^2-72=12x are x=6(1+sqrt(3)),x=6(1-sqrt(3))

Find the zeros of x^2-72=12x

The zeros of x^2-72=12x are x=6(1+sqrt(3)),x=6(1-sqrt(3))

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x^{2} - 72 = 12 x

x = 6 (1 + 3), x = 6 (1 - 3)

Solution steps

x^{2} - 72 = 12 x

Move

12 x

to the left side

x^{2} - 72 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 12 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 72) = 123

x_{1, 2} = \frac{- ( - 12 ) \pm 12 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 3}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 12 3}{2 \cdot 1}

x = \frac{- ( - 12 ) + 12 3}{2 \cdot 1} : 6 (1 + 3)

x = \frac{- ( - 12 ) - 12 3}{2 \cdot 1} : 6 (1 - 3)

The solutions to the quadratic equation are:

x = 6 (1 + 3), x = 6 (1 - 3)

M - 9 = - 13

2 - 2 x^{2} + 8 x = 7

k = 6 (- 5) + 100

2 x^{2} - 7 x + 1 = 0

lo g_{10} (3 x) < lo g_{10} (7 x - 8)

What are the solutions to the equation x^2-72=12x ?
The solutions to the equation x^2-72=12x are x=6(1+sqrt(3)),x=6(1-sqrt(3))
Find the zeros of x^2-72=12x
The zeros of x^2-72=12x are x=6(1+sqrt(3)),x=6(1-sqrt(3))