What is log_{5}(k^2-25)-log_{5}(k)-5 ?

The solution to log_{5}(k^2-25)-log_{5}(k)-5 is log_{5}((k^2-25)/k)-5

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simplify log_{5}(k^2-25)-log_{5}(k)-5

simplify

lo g_{5} (k^{2} - 25) - lo g_{5} (k) - 5

lo g_{5} (\frac{k ^{2} - 25}{k}) - 5

Solution steps

lo g_{5} (k^{2} - 25) - lo g_{5} (k) - 5

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{5} (k^{2} - 25) - lo g_{5} (k) = lo g_{5} (\frac{k ^{2} - 25}{k})

= lo g_{5} (\frac{k ^{2} - 25}{k}) - 5

ln (9) + ln (4)

lo g_{10} (\frac{3 x}{2})

ln (x^{6}) - 2 ln (x^{5})

lo g_{10} (\frac{3 x}{4})

lo g_{10} (\frac{7 x}{11})

What is log_{5}(k^2-25)-log_{5}(k)-5 ?
The solution to log_{5}(k^2-25)-log_{5}(k)-5 is log_{5}((k^2-25)/k)-5