What is 6log_{b}(t)-log_{b}(s) ?

The solution to 6log_{b}(t)-log_{b}(s) is log_{b}((t^6)/s)

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simplify 6log_{b}(t)-log_{b}(s)

simplify

6 lo g_{b} (t) - lo g_{b} (s)

lo g_{b} (\frac{t ^{6}}{s})

Solution steps

6 lo g_{b} (t) - lo g_{b} (s)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

6 lo g_{b} (t) = lo g_{b} (t^{6})

= lo g_{b} (t^{6}) - lo g_{b} (s)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{b} (t^{6}) - lo g_{b} (s) = lo g_{b} (\frac{t ^{6}}{s})

= lo g_{b} (\frac{t ^{6}}{s})

ln (x y)

lo g_{4} (9) - lo g_{4} (y)

- lo g_{10} (6.9 \cdot 1 0^{- 8})

lo g_{3} (m) + lo g_{3} (m + 1) - lo g_{2} (m + 6)

lo g_{4} (\frac{5 x ^{3}}{y})

What is 6log_{b}(t)-log_{b}(s) ?
The solution to 6log_{b}(t)-log_{b}(s) is log_{b}((t^6)/s)