What are the solutions to the equation 6q^2-3q=5q^2-8q+24 ?

The solutions to the equation 6q^2-3q=5q^2-8q+24 are q=-8,q=3

Find the zeros of 6q^2-3q=5q^2-8q+24

The zeros of 6q^2-3q=5q^2-8q+24 are q=-8,q=3

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6 q^{2} - 3 q = 5 q^{2} - 8 q + 24

q = - 8, q = 3

Solution steps

6 q^{2} - 3 q = 5 q^{2} - 8 q + 24

Switch sides

5 q^{2} - 8 q + 24 = 6 q^{2} - 3 q

Move

3 q

to the left side

5 q^{2} - 5 q + 24 = 6 q^{2}

Move

6 q^{2}

to the left side

- q^{2} - 5 q + 24 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 24}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 24 = 11

q_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- ( - 5 ) + 11}{2 ( - 1 )}, q_{2} = \frac{- ( - 5 ) - 11}{2 ( - 1 )}

q = \frac{- ( - 5 ) + 11}{2 ( - 1 )} : - 8

q = \frac{- ( - 5 ) - 11}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

q = - 8, q = 3

m^{2} + 6 m + 9 = 0

x + 1 + 4 \leq 9

3 - (2)^{4}

\frac{5 ! 6 !}{3 ! 8 !}

x^{2} - 20 x - 44 = 0

What are the solutions to the equation 6q^2-3q=5q^2-8q+24 ?
The solutions to the equation 6q^2-3q=5q^2-8q+24 are q=-8,q=3
Find the zeros of 6q^2-3q=5q^2-8q+24
The zeros of 6q^2-3q=5q^2-8q+24 are q=-8,q=3