What is log_{10}(8^2)-log_{10}(125^2) ?

The solution to log_{10}(8^2)-log_{10}(125^2) is log_{10}(64/15625)

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simplify log_{10}(8^2)-log_{10}(125^2)

simplify

lo g_{10} (8^{2}) - lo g_{10} (12 5^{2})

lo g_{10} (\frac{64}{15625})

Decimal Notation

- 2.38764 \dots

Solution steps

lo g_{10} (8^{2}) - lo g_{10} (12 5^{2})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (8^{2}) - lo g_{10} (12 5^{2}) = lo g_{10} (\frac{8 ^{2}}{12 5 ^{2}})

= lo g_{10} (\frac{8 ^{2}}{12 5 ^{2}})

\frac{8 ^{2}}{12 5 ^{2}} = \frac{64}{15625}

= lo g_{10} (\frac{64}{15625})

lo g_{10} (3 (x + 1)^{2})

ln (x) - ln (x + 1)

9 ln (x) - \frac{1}{5} ln (y)

3 ln (x) - 2 ln (x - 1) + 1

3 lo g_{10} (3) - 2 lo g_{10} (6)

What is log_{10}(8^2)-log_{10}(125^2) ?
The solution to log_{10}(8^2)-log_{10}(125^2) is log_{10}(64/15625)