What is ln((s^2+9)/(s^2+1)) ?

The solution to ln((s^2+9)/(s^2+1)) is ln(s^2+9)-ln(s^2+1)

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simplify ln((s^2+9)/(s^2+1))

simplify

ln (\frac{s ^{2} + 9}{s ^{2} + 1})

ln (s^{2} + 9) - ln (s^{2} + 1)

Solution steps

ln (\frac{s ^{2} + 9}{s ^{2} + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{s ^{2} + 9}{s ^{2} + 1}) = ln (s^{2} + 9) - ln (s^{2} + 1)

= ln (s^{2} + 9) - ln (s^{2} + 1)

ln (\frac{5}{6 x ^{6} y})

ln (\frac{5}{12})

lo g_{a} (ab) - lo g_{a} (a^{3} b)

lo g_{3} (10) - lo g_{3} (5)

lo g_{9} (z) + \frac{1}{2} lo g_{9} (x) + \frac{1}{2} lo g_{9} (y)

What is ln((s^2+9)/(s^2+1)) ?
The solution to ln((s^2+9)/(s^2+1)) is ln(s^2+9)-ln(s^2+1)