What is ln((e^x+1)/(e^x-1)) ?

The solution to ln((e^x+1)/(e^x-1)) is ln(e^x+1)-ln(e^x-1)

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simplify ln((e^x+1)/(e^x-1))

simplify

ln (\frac{e ^{x} + 1}{e ^{x} - 1})

ln (e^{x} + 1) - ln (e^{x} - 1)

Solution steps

ln (\frac{e ^{x} + 1}{e ^{x} - 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{e ^{x} + 1}{e ^{x} - 1}) = ln (e^{x} + 1) - ln (e^{x} - 1)

= ln (e^{x} + 1) - ln (e^{x} - 1)

- lo g_{10} (3.9 \cdot 1 0^{- 4})

lo g_{5} (x) - lo g_{5} (x^{9})

\frac{1}{2} (lo g_{7} (a) + lo g_{7} (b))

ln (\frac{139}{7})

lo g_{2} (16 x)

What is ln((e^x+1)/(e^x-1)) ?
The solution to ln((e^x+1)/(e^x-1)) is ln(e^x+1)-ln(e^x-1)