What is log_{10}(4x)+log_{10}(x) ?

The solution to log_{10}(4x)+log_{10}(x) is log_{10}(4x^2)

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simplify log_{10}(4x)+log_{10}(x)

simplify

lo g_{10} (4 x) + lo g_{10} (x)

lo g_{10} (4 x^{2})

Solution steps

lo g_{10} (4 x) + lo g_{10} (x)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (4 x) + lo g_{10} (x) = lo g_{10} (4 xx)

= lo g_{10} (4 xx)

Simplify

4 xx : 4 x^{2}

= lo g_{10} (4 x^{2})

2 ln (x) + 3 ln (y) - ln (z)

7 ln (x) - \frac{1}{3} ln (y)

ln (x^{6} 7 - x)

- lo g_{10} (7.9 \cdot 1 0^{- 9})

lo g_{2} (x y) - \frac{1}{3} lo g_{2} (x^{2})

What is log_{10}(4x)+log_{10}(x) ?
The solution to log_{10}(4x)+log_{10}(x) is log_{10}(4x^2)