What are the solutions to the equation 9x^2+48x+64=0 ?

The solutions to the equation 9x^2+48x+64=0 are x=-8/3

Find the zeros of 9x^2+48x+64=0

The zeros of 9x^2+48x+64=0 are x=-8/3

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9 x^{2} + 48 x + 64 = 0

x = - \frac{8}{3}

Decimal Notation

x = - 2.66666 \dots

Solution steps

9 x^{2} + 48 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 9 \cdot 64}{2 \cdot 9}

4 8^{2} - 4 \cdot 9 \cdot 64 = 0

x_{1, 2} = \frac{- 48 \pm 0}{2 \cdot 9}

x = \frac{- 48}{2 \cdot 9}

\frac{- 48}{2 \cdot 9} = - \frac{8}{3}

x = - \frac{8}{3}

The solution to the quadratic equation is:

x = - \frac{8}{3}

∣ 8 x + 2 ∣ < 42

\frac{2}{3} + x = 3

- 5 - x = - 3

- 2 a - 9 = 6 a + 15

x^{2} + x - 72

What are the solutions to the equation 9x^2+48x+64=0 ?
The solutions to the equation 9x^2+48x+64=0 are x=-8/3
Find the zeros of 9x^2+48x+64=0
The zeros of 9x^2+48x+64=0 are x=-8/3