What is expand log_{6}((36)/(sqrt(x+1))) ?

The solution to expand log_{6}((36)/(sqrt(x+1))) is 2-log_{6}(sqrt(x+1))

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expand log_{6}((36)/(sqrt(x+1)))

expand

lo g_{6} (\frac{36}{x + 1})

2 - lo g_{6} (x + 1)

Solution steps

lo g_{6} (\frac{36}{x + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{6} (\frac{36}{x + 1}) = lo g_{6} (36) - lo g_{6} (x + 1)

= lo g_{6} (36) - lo g_{6} (x + 1)

lo g_{6} (36) = 2

= 2 - lo g_{6} (x + 1)

ln (x \cdot e^{y})

lo g_{10} (\frac{y}{1})

ln (\frac{1 - 1 - 4 x ^{2}}{2 x})

- lo g_{10} (1.34 \cdot 1 0^{- 3})

lo g_{3} (4) + lo g_{3} (11)

What is expand log_{6}((36)/(sqrt(x+1))) ?
The solution to expand log_{6}((36)/(sqrt(x+1))) is 2-log_{6}(sqrt(x+1))