What is ln((e^x-1)/(e^x+1)) ?

The solution to ln((e^x-1)/(e^x+1)) is ln(e^x-1)-ln(e^x+1)

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simplify ln((e^x-1)/(e^x+1))

simplify

ln (\frac{e ^{x} - 1}{e ^{x} + 1})

ln (e^{x} - 1) - ln (e^{x} + 1)

Solution steps

ln (\frac{e ^{x} - 1}{e ^{x} + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{e ^{x} - 1}{e ^{x} + 1}) = ln (e^{x} - 1) - ln (e^{x} + 1)

= ln (e^{x} - 1) - ln (e^{x} + 1)

lo g_{10} (\frac{x ^{4} z ^{3}}{y})

- lo g_{10} (2 \cdot 1 0^{- 6})

ln (\frac{e ^{4}}{10})

- 3 (\frac{1}{2} ln (2^{2} - 9) - \frac{1}{2} ln ((- 2)^{2} - 9))

- lo g_{10} (2.5 \cdot 1 0^{- 3})

What is ln((e^x-1)/(e^x+1)) ?
The solution to ln((e^x-1)/(e^x+1)) is ln(e^x-1)-ln(e^x+1)