What is 3log_{4}(n)+log_{4}(m) ?

The solution to 3log_{4}(n)+log_{4}(m) is log_{4}(n^3m)

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simplify 3log_{4}(n)+log_{4}(m)

simplify

3 lo g_{4} (n) + lo g_{4} (m)

lo g_{4} (n^{3} m)

Solution steps

3 lo g_{4} (n) + lo g_{4} (m)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{4} (n) = lo g_{4} (n^{3})

= lo g_{4} (n^{3}) + lo g_{4} (m)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{4} (n^{3}) + lo g_{4} (m) = lo g_{4} (n^{3} m)

= lo g_{4} (n^{3} m)

3 ln (2) + ln (x - 2) - 2 ln (7)

lo g_{2} (\frac{4}{x + 3})

lo g_{10} (\frac{x ^{2}}{y ^{5}})

(lo g_{c} (x) - lo g_{c} (y)) + 7 lo g_{c} (v)

10 lo g_{6} (x) - 2 lo g_{6} (y)

What is 3log_{4}(n)+log_{4}(m) ?
The solution to 3log_{4}(n)+log_{4}(m) is log_{4}(n^3m)