What is 1/(2log_{2)(3)}+1/(2log_{5)(3)} ?

The solution to 1/(2log_{2)(3)}+1/(2log_{5)(3)} is (log_{5}(3)+log_{2}(3))/(2log_{2)(3)log_{5}(3)}

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simplify 1/(2log_{2)(3)}+1/(2log_{5)(3)}

simplify

\frac{1}{2 lo g _{2} ( 3 )} + \frac{1}{2 lo g _{5} ( 3 )}

\frac{lo g _{5} ( 3 ) + lo g _{2} ( 3 )}{2 lo g _{2} ( 3 ) lo g _{5} ( 3 )}

Decimal Notation

1.04795 \dots

Solution steps

\frac{1}{2 lo g _{2} ( 3 )} + \frac{1}{2 lo g _{5} ( 3 )}

Least Common Multiplier of

2 lo g_{2} (3), 2 lo g_{5} (3) : 2 lo g_{2} (3) lo g_{5} (3)

Adjust Fractions based on the LCM

= \frac{lo g _{5} ( 3 )}{2 lo g _{2} ( 3 ) lo g _{5} ( 3 )} + \frac{lo g _{2} ( 3 )}{2 lo g _{2} ( 3 ) lo g _{5} ( 3 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{lo g _{5} ( 3 ) + lo g _{2} ( 3 )}{2 lo g _{2} ( 3 ) lo g _{5} ( 3 )}

ln (\frac{9}{7})

ln (x^{2} y^{6} z)

ln (x^{9} 3 - x)

What is 1/(2log_{2)(3)}+1/(2log_{5)(3)} ?
The solution to 1/(2log_{2)(3)}+1/(2log_{5)(3)} is (log_{5}(3)+log_{2}(3))/(2log_{2)(3)log_{5}(3)}