What is log_{4}((x^2\sqrt[3]{4x+1})/(16)) ?

The solution to log_{4}((x^2\sqrt[3]{4x+1})/(16)) is log_{2}(x)+log_{4}(\sqrt[3]{4x+1})-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{4}((x^2\sqrt[3]{4x+1})/(16))

simplify

Solution steps

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{4} (16) = 2

2 lo g_{6} (x) - 2 lo g_{6} (y)

\frac{1}{3} lo g_{b} (x) + 3 lo g_{b} (y) - 5 lo g_{b} (x)

lo g_{n} (\frac{2 a}{7 y})

4 lo g_{2} (x) - 5 lo g_{2} (y)

What is log_{4}((x^2\sqrt[3]{4x+1})/(16)) ?
The solution to log_{4}((x^2\sqrt[3]{4x+1})/(16)) is log_{2}(x)+log_{4}(\sqrt[3]{4x+1})-2