What is log_{10}(9)+4*log_{10}(27)-log_{10}(81) ?

The solution to log_{10}(9)+4*log_{10}(27)-log_{10}(81) is 10log_{10}(3)

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simplify log_{10}(9)+4*log_{10}(27)-log_{10}(81)

simplify

lo g_{10} (9) + 4 \cdot lo g_{10} (27) - lo g_{10} (81)

10 lo g_{10} (3)

Decimal Notation

4.77121 \dots

Solution steps

lo g_{10} (9) + 4 lo g_{10} (27) - lo g_{10} (81)

lo g_{10} (9) - lo g_{10} (81) = - 2 lo g_{10} (3)

= - 2 lo g_{10} (3) + 4 lo g_{10} (27)

4 lo g_{10} (27) = 12 lo g_{10} (3)

= - 2 lo g_{10} (3) + 12 lo g_{10} (3)

Add similar elements:

- 2 lo g_{10} (3) + 12 lo g_{10} (3) = 10 lo g_{10} (3)

= 10 lo g_{10} (3)

\frac{1}{2} lo g_{10} (x) + 4 lo g_{10} (x - 1)

- \frac{1}{2} ln (y + 1) + \frac{1}{2} ln (y - 1)

lo g_{7} (7 m n^{4})

lo g_{10} (\frac{a b ^{7}}{c ^{8}})

lo g_{2} (A B^{2})

What is log_{10}(9)+4*log_{10}(27)-log_{10}(81) ?
The solution to log_{10}(9)+4*log_{10}(27)-log_{10}(81) is 10log_{10}(3)