What are the solutions to the equation x^2+13x+22=7 ?

The solutions to the equation x^2+13x+22=7 are x=(-13+sqrt(109))/2 ,x=(-13-sqrt(109))/2

Find the zeros of x^2+13x+22=7

The zeros of x^2+13x+22=7 are x=(-13+sqrt(109))/2 ,x=(-13-sqrt(109))/2

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x^{2} + 13 x + 22 = 7

x = \frac{- 13 + 109}{2}, x = \frac{- 13 - 109}{2}

Decimal Notation

x = - 1.27984 \dots, x = - 11.72015 \dots

Solution steps

x^{2} + 13 x + 22 = 7

Move

7

to the left side

x^{2} + 13 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 15 = 109

x_{1, 2} = \frac{- 13 \pm 109}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 109}{2 \cdot 1}, x_{2} = \frac{- 13 - 109}{2 \cdot 1}

x = \frac{- 13 + 109}{2 \cdot 1} : \frac{- 13 + 109}{2}

x = \frac{- 13 - 109}{2 \cdot 1} : \frac{- 13 - 109}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 109}{2}, x = \frac{- 13 - 109}{2}

\frac{17}{17}

\frac{1}{8} + \frac{3}{16}

(\frac{5}{7})^{2}

x + \frac{3}{4} = 16

35 = 70 t - 5 t^{2}

What are the solutions to the equation x^2+13x+22=7 ?
The solutions to the equation x^2+13x+22=7 are x=(-13+sqrt(109))/2 ,x=(-13-sqrt(109))/2
Find the zeros of x^2+13x+22=7
The zeros of x^2+13x+22=7 are x=(-13+sqrt(109))/2 ,x=(-13-sqrt(109))/2