What is 2log_{y}(3)+log_{y}(2) ?

The solution to 2log_{y}(3)+log_{y}(2) is log_{y}(18)

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simplify 2log_{y}(3)+log_{y}(2)

simplify

2 lo g_{y} (3) + lo g_{y} (2)

lo g_{y} (18)

Solution steps

2 lo g_{y} (3) + lo g_{y} (2)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

2 lo g_{y} (3) = lo g_{y} (3^{2})

= lo g_{y} (3^{2}) + lo g_{y} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{y} (3^{2}) + lo g_{y} (2) = lo g_{y} (3^{2} \cdot 2)

= lo g_{y} (3^{2} \cdot 2)

3^{2} \cdot 2 = 18

= lo g_{y} (18)

2 lo g_{10} (x) - 6 lo g_{10} (y)

lo g_{10} (\frac{y}{x ^{5}})

(lo g_{c} (x) - lo g_{c} (y)) + 8 lo g_{c} (v)

lo g_{2} (e^{- x} cos (π x))

ln (\frac{1}{2 π})

What is 2log_{y}(3)+log_{y}(2) ?
The solution to 2log_{y}(3)+log_{y}(2) is log_{y}(18)