What is log_{10}(2)+log_{10}(4)-log_{10}(7) ?

The solution to log_{10}(2)+log_{10}(4)-log_{10}(7) is log_{10}(8/7)

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simplify log_{10}(2)+log_{10}(4)-log_{10}(7)

simplify

lo g_{10} (2) + lo g_{10} (4) - lo g_{10} (7)

lo g_{10} (\frac{8}{7})

Decimal Notation

0.05799 \dots

Solution steps

lo g_{10} (2) + lo g_{10} (4) - lo g_{10} (7)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (4) - lo g_{10} (7) = lo g_{10} (\frac{4}{7})

= lo g_{10} (2) + lo g_{10} (\frac{4}{7})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (2) + lo g_{10} (\frac{4}{7}) = lo g_{10} (2 \cdot \frac{4}{7})

= lo g_{10} (2 \cdot \frac{4}{7})

2 \cdot \frac{4}{7} = \frac{8}{7}

= lo g_{10} (\frac{8}{7})

lo g_{3} (\frac{x ^{8} y ^{4}}{6})

ln (x^{13} 2 - x)

lo g_{10} (x - 2) + lo g_{10} (x) - lo g_{10} (8)

lo g_{10} (z x^{8})

\frac{1}{2} lo g_{2} (405)

What is log_{10}(2)+log_{10}(4)-log_{10}(7) ?
The solution to log_{10}(2)+log_{10}(4)-log_{10}(7) is log_{10}(8/7)