What is 4log_{10}(2x) ?

The solution to 4log_{10}(2x) is 4log_{10}(2)+4log_{10}(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 4log_{10}(2x)

simplify

4 lo g_{10} (2 x)

4 lo g_{10} (2) + 4 lo g_{10} (x)

Solution steps

4 lo g_{10} (2 x)

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{10} (2 x) = lo g_{10} (2) + lo g_{10} (x)

= 4 (lo g_{10} (2) + lo g_{10} (x))

Apply the distributive law:

a (b + c) = ab + a c

4 (lo g_{10} (2) + lo g_{10} (x)) = 4 lo g_{10} (2) + 4 lo g_{10} (x)

= 4 lo g_{10} (2) + 4 lo g_{10} (x)

lo g_{9} (8 ab)

ln (x (x + 9))

- lo g_{6} (3) + 2 lo g_{6} (3) + lo g_{6} (5)

ln (2 e) - ln (e)

What is 4log_{10}(2x) ?
The solution to 4log_{10}(2x) is 4log_{10}(2)+4log_{10}(x)