What is log_{7}(x)+log_{7}(x-3)-2 ?

The solution to log_{7}(x)+log_{7}(x-3)-2 is log_{7}(x(x-3))-2

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simplify log_{7}(x)+log_{7}(x-3)-2

simplify

lo g_{7} (x) + lo g_{7} (x - 3) - 2

lo g_{7} (x (x - 3)) - 2

Solution steps

lo g_{7} (x) + lo g_{7} (x - 3) - 2

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{7} (x) + lo g_{7} (x - 3) = lo g_{7} (x (x - 3))

= lo g_{7} (x (x - 3)) - 2

3 ln (x) + 4 ln (y) - 5 ln (z)

lo g_{2} (3) - lo g_{2} (5)

lo g_{4} (\frac{( 3 x - 7 )}{( 2 x + 1 ) 5 x + 7})

2 lo g_{b} (3) + lo g_{b} (6)

lo g_{10} (\frac{x ^{5}}{2})

What is log_{7}(x)+log_{7}(x-3)-2 ?
The solution to log_{7}(x)+log_{7}(x-3)-2 is log_{7}(x(x-3))-2