What is log_{10}(x)-log_{10}(2) ?

The solution to log_{10}(x)-log_{10}(2) is log_{10}(x/2)

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simplify log_{10}(x)-log_{10}(2)

simplify

lo g_{10} (x) - lo g_{10} (2)

lo g_{10} (\frac{x}{2})

Solution steps

lo g_{10} (x) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (x) - lo g_{10} (2) = lo g_{10} (\frac{x}{2})

= lo g_{10} (\frac{x}{2})

lo g_{10} (100 y^{4} \times \frac{y + 5}{y - 5})

lo g_{4} (\frac{16}{x + 7})

\frac{3}{2} \cdot lo g_{3} (a) - \frac{1}{4} \cdot lo g_{3} (16 a^{2})

ln (\frac{e ^{x}}{1 + e ^{x}})

lo g_{10} (\frac{5 x}{y})

What is log_{10}(x)-log_{10}(2) ?
The solution to log_{10}(x)-log_{10}(2) is log_{10}(x/2)