What is log_{2}(3)+log_{2}(6) ?

The solution to log_{2}(3)+log_{2}(6) is log_{2}(18)

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simplify log_{2}(3)+log_{2}(6)

simplify

lo g_{2} (3) + lo g_{2} (6)

lo g_{2} (18)

Decimal Notation

4.16992 \dots

Solution steps

lo g_{2} (3) + lo g_{2} (6)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (3) + lo g_{2} (6) = lo g_{2} (3 \cdot 6)

= lo g_{2} (3 \cdot 6)

Multiply the numbers:

3 \cdot 6 = 18

= lo g_{2} (18)

ln (\frac{e ^{7}}{14})

\frac{1}{2} lo g_{3} (x) - 2 lo g_{3} (y) - lo g_{3} (z)

ln (5 e^{2})

lo g_{10} (z^{5} x^{3} y)

What is log_{2}(3)+log_{2}(6) ?
The solution to log_{2}(3)+log_{2}(6) is log_{2}(18)