What is 4log_{10}(3)+log_{10}(2) ?

The solution to 4log_{10}(3)+log_{10}(2) is log_{10}(162)

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simplify 4log_{10}(3)+log_{10}(2)

simplify

4 lo g_{10} (3) + lo g_{10} (2)

lo g_{10} (162)

Decimal Notation

2.20951 \dots

Solution steps

4 lo g_{10} (3) + lo g_{10} (2)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

4 lo g_{10} (3) = lo g_{10} (3^{4})

= lo g_{10} (3^{4}) + lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (3^{4}) + lo g_{10} (2) = lo g_{10} (3^{4} \cdot 2)

= lo g_{10} (3^{4} \cdot 2)

3^{4} \cdot 2 = 162

= lo g_{10} (162)

lo g_{10} (x^{3}) - lo g_{10} (y^{2})

\frac{1}{3} ln (x - 3) - 4 ln (z) + ln (y + 7)

lo g_{10} ((\frac{p ^{4}}{q ^{7}})^{2})

- lo g_{10} (2.6 \cdot 1 0^{- 4})

lo g_{x} (\frac{1}{16})

What is 4log_{10}(3)+log_{10}(2) ?
The solution to 4log_{10}(3)+log_{10}(2) is log_{10}(162)