What is expand ln((ex^2)/y) ?

The solution to expand ln((ex^2)/y) is 1+2ln(x)-ln(y)

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expand ln((ex^2)/y)

expand

ln (\frac{e x ^{2}}{y})

1 + 2 ln (x) - ln (y)

Solution steps

ln (\frac{e x ^{2}}{y})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{e x ^{2}}{y}) = ln (e x^{2}) - ln (y)

= ln (e x^{2}) - ln (y)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (e x^{2}) = ln (e) + ln (x^{2})

= ln (e) + ln (x^{2}) - ln (y)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (x^{2}) = 2 ln (x)

= ln (e) + 2 ln (x) - ln (y)

Apply log rule:

lo g_{a} (a) = 1

= 1 + 2 ln (x) - ln (y)

- lo g_{10} (6.4 \cdot 1 0^{- 4})

- lo g_{10} (6.3 \cdot 1 0^{- 8})

lo g_{6} (13 x)

lo g_{7} (\frac{1}{49} x^{2} y^{3})

- 2 lo g_{3} (\frac{1}{x}) + \frac{1}{3} lo g_{3} (x)

What is expand ln((ex^2)/y) ?
The solution to expand ln((ex^2)/y) is 1+2ln(x)-ln(y)