What is expand-2.5log_{10}(B/(B_{0)}) ?

The solution to expand-2.5log_{10}(B/(B_{0)}) is -2.5(log_{10}(B)-log_{10}(B))

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expand-2.5log_{10}(B/(B_{0)})

expand

- 2.5 lo g_{10} (\frac{B}{B _{0}})

- 2.5 (lo g_{10} (B) - lo g_{10} (B))

Solution steps

- 2.5 lo g_{10} (\frac{B}{B _{0}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{B}{B _{0}}) = lo g_{10} (B) - lo g_{10} (B_{0})

= - 2.5 (lo g_{10} (B) - lo g_{10} (B_{0}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (B_{0}) = lo g_{10} (B)

= - 2.5 (lo g_{10} (B) - lo g_{10} (B))

lo g_{3} (125) - lo g_{3} (5)

lo g_{1000} (10 x)

lo g_{3} (ab) - lo g_{3} (b^{3})

ln (\frac{e ^{4}}{11})

What is expand-2.5log_{10}(B/(B_{0)}) ?
The solution to expand-2.5log_{10}(B/(B_{0)}) is -2.5(log_{10}(B)-log_{10}(B))