What is log_{b}((p^2q^7)/(m^4b^9)) ?

The solution to log_{b}((p^2q^7)/(m^4b^9)) is 2log_{b}(p)+7log_{b}(q)-4log_{b}(m)-9

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simplify log_{b}((p^2q^7)/(m^4b^9))

simplify

lo g_{b} (\frac{p ^{2} q ^{7}}{m ^{4} b ^{9}})

2 lo g_{b} (p) + 7 lo g_{b} (q) - 4 lo g_{b} (m) - 9

Solution steps

lo g_{b} (\frac{p ^{2} q ^{7}}{m ^{4} b ^{9}})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{b} (\frac{p ^{2} q ^{7}}{m ^{4} b ^{9}}) = lo g_{b} (p^{2} q^{7}) - lo g_{b} (m^{4} b^{9})

= lo g_{b} (p^{2} q^{7}) - lo g_{b} (m^{4} b^{9})

lo g_{b} (p^{2} q^{7}) = 2 lo g_{b} (p) + 7 lo g_{b} (q)

lo g_{b} (m^{4} b^{9}) = 4 lo g_{b} (m) + 9

= 2 lo g_{b} (p) + 7 lo g_{b} (q) - (4 lo g_{b} (m) + 9)

Apply the distributive law:

- (a + b) = - a - b

- (4 lo g_{b} (m) + 9) = - 4 lo g_{b} (m) - 9

= 2 lo g_{b} (p) + 7 lo g_{b} (q) - 4 lo g_{b} (m) - 9

2 ln ∣ cot (x) ∣ + 2 ln ∣ sin (x) ∣

3 lo g_{3} (2) + 2 lo g_{3} (4) - lo g_{3} (6)

2 lo g_{b} (x) + 9 lo g_{b} (z)

lo g_{5} (\frac{2 x - 1}{5})

4 ln (x) + 3 ln (y) - 6 ln (z)

What is log_{b}((p^2q^7)/(m^4b^9)) ?
The solution to log_{b}((p^2q^7)/(m^4b^9)) is 2log_{b}(p)+7log_{b}(q)-4log_{b}(m)-9