What is log_{10}((7z)/9) ?

The solution to log_{10}((7z)/9) is log_{10}(7)+log_{10}(z)-2log_{10}(3)

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simplify log_{10}((7z)/9)

simplify

lo g_{10} (\frac{7 z}{9})

lo g_{10} (7) + lo g_{10} (z) - 2 lo g_{10} (3)

Solution steps

lo g_{10} (\frac{7 z}{9})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{7 z}{9}) = lo g_{10} (7 z) - lo g_{10} (9)

= lo g_{10} (7 z) - lo g_{10} (9)

lo g_{10} (7 z) = lo g_{10} (7) + lo g_{10} (z)

lo g_{10} (9) = 2 lo g_{10} (3)

= lo g_{10} (7) + lo g_{10} (z) - 2 lo g_{10} (3)

lo g_{7} (7 m n^{4})

\frac{ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

\frac{1}{2} lo g_{2} (127)

- lo g_{10} (3.1 \cdot 1 0^{- 5})

What is log_{10}((7z)/9) ?
The solution to log_{10}((7z)/9) is log_{10}(7)+log_{10}(z)-2log_{10}(3)