What is log_{10}(0.0001)-log_{10}(0.1) ?

The solution to log_{10}(0.0001)-log_{10}(0.1) is -3

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simplify log_{10}(0.0001)-log_{10}(0.1)

simplify

lo g_{10} (0.0001) - lo g_{10} (0.1)

- 3

Solution steps

lo g_{10} (0.0001) - lo g_{10} (0.1)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (0.0001) - lo g_{10} (0.1) = lo g_{10} (\frac{0.0001}{0.1})

= lo g_{10} (\frac{0.0001}{0.1})

\frac{0.0001}{0.1} = \frac{1}{1000}

= lo g_{10} (\frac{1}{1000})

\frac{1}{1000} = 1 0^{- 3}

= lo g_{10} (1 0^{- 3})

Apply log rule:

lo g_{a} (a^{b}) = b

= - 3

4 lo g_{10} (x) + 3 lo g_{10} (y)

ln (\frac{( d - r ) ^{2}}{r ^{2}})

\frac{1}{2} (lo g_{5} (s) + lo g_{5} (t))

- lo g_{10} (1.2 \cdot 1 0^{- 5})

- lo g_{10} (1.34 \times 1 0^{- 3})

What is log_{10}(0.0001)-log_{10}(0.1) ?
The solution to log_{10}(0.0001)-log_{10}(0.1) is -3