What is 2log_{m}(a)-3log_{m}(b^2) ?

The solution to 2log_{m}(a)-3log_{m}(b^2) is 2log_{m}(a)-6log_{m}(b)

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simplify 2log_{m}(a)-3log_{m}(b^2)

simplify

2 lo g_{m} (a) - 3 lo g_{m} (b^{2})

2 lo g_{m} (a) - 6 lo g_{m} (b)

Solution steps

2 lo g_{m} (a) - 3 lo g_{m} (b^{2})

Simplify

3 lo g_{m} (b^{2}) : 6 lo g_{m} (b)

= 2 lo g_{m} (a) - 6 lo g_{m} (b)

\frac{2}{3} lo g_{b} (27) + 2 lo g_{b} (2) - lo g_{b} (3)

- \frac{8}{12} lo g_{2} (\frac{8}{12}) - \frac{4}{12} lo g_{2} (\frac{4}{12})

ln \frac{x}{2} + 1 - ln \frac{x}{2} - 1

lo g_{10} (12 x) - lo g_{10} (3 x)

ln (4 h - 8) - ln (4)

What is 2log_{m}(a)-3log_{m}(b^2) ?
The solution to 2log_{m}(a)-3log_{m}(b^2) is 2log_{m}(a)-6log_{m}(b)