What is expand log_{8}((64)/(sqrt(x+1))) ?

The solution to expand log_{8}((64)/(sqrt(x+1))) is 2-log_{8}(sqrt(x+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand log_{8}((64)/(sqrt(x+1)))

expand

lo g_{8} (\frac{64}{x + 1})

2 - lo g_{8} (x + 1)

Solution steps

lo g_{8} (\frac{64}{x + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{8} (\frac{64}{x + 1}) = lo g_{8} (64) - lo g_{8} (x + 1)

= lo g_{8} (64) - lo g_{8} (x + 1)

lo g_{8} (64) = 2

= 2 - lo g_{8} (x + 1)

9 ln (a) - 6 ln (b)

2 lo g_{10} (2) + 2 lo g_{10} (3)

2 ln (x) + 5 ln (y) - 6 ln (z)

x ln (2) + 5 ln (x - 1) - 2 ln (x + 3)

ln (\frac{243}{625})

What is expand log_{8}((64)/(sqrt(x+1))) ?
The solution to expand log_{8}((64)/(sqrt(x+1))) is 2-log_{8}(sqrt(x+1))