What are the solutions to the equation x^2-9=4x ?

The solutions to the equation x^2-9=4x are x=2+sqrt(13),x=2-sqrt(13)

Find the zeros of x^2-9=4x

The zeros of x^2-9=4x are x=2+sqrt(13),x=2-sqrt(13)

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x^{2} - 9 = 4 x

x = 2 + 13, x = 2 - 13

Solution steps

x^{2} - 9 = 4 x

Move

4 x

to the left side

x^{2} - 9 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 9) = 213

x_{1, 2} = \frac{- ( - 4 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 13}{2 \cdot 1} : 2 + 13

x = \frac{- ( - 4 ) - 2 13}{2 \cdot 1} : 2 - 13

The solutions to the quadratic equation are:

x = 2 + 13, x = 2 - 13

∣ 2 x - 4 ∣ \leq 8

\frac{3}{2} x - 2 + 1 \leq 2

- 1 - \frac{4}{3}

1^{1}

m^{2} + 18 m - 3 = 0

What are the solutions to the equation x^2-9=4x ?
The solutions to the equation x^2-9=4x are x=2+sqrt(13),x=2-sqrt(13)
Find the zeros of x^2-9=4x
The zeros of x^2-9=4x are x=2+sqrt(13),x=2-sqrt(13)