What is log_{10}(2)+log_{10}(5)-log_{10}(3) ?

The solution to log_{10}(2)+log_{10}(5)-log_{10}(3) is 1-log_{10}(3)

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simplify log_{10}(2)+log_{10}(5)-log_{10}(3)

simplify

lo g_{10} (2) + lo g_{10} (5) - lo g_{10} (3)

1 - lo g_{10} (3)

Decimal Notation

0.52287 \dots

Solution steps

lo g_{10} (2) + lo g_{10} (5) - lo g_{10} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (2) + lo g_{10} (5) = lo g_{10} (2 \cdot 5)

= lo g_{10} (2 \cdot 5) - lo g_{10} (3)

lo g_{10} (2 \cdot 5) = 1

= 1 - lo g_{10} (3)

lo g_{4} (3 x y)

2 lo g_{a} (7) + lo g_{a} (4) - lo g_{a} (10)

8 lo g_{10} (x) - 7 lo g_{10} (x + 1)

lo g_{4} (10) + lo g_{4} (7) + 4 lo g_{4} (3)

lo g_{10} (x) + lo g_{10} (4)

What is log_{10}(2)+log_{10}(5)-log_{10}(3) ?
The solution to log_{10}(2)+log_{10}(5)-log_{10}(3) is 1-log_{10}(3)