What is log_{10}(a-b)-log_{10}(3) ?

The solution to log_{10}(a-b)-log_{10}(3) is log_{10}((a-b)/3)

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simplify log_{10}(a-b)-log_{10}(3)

simplify

lo g_{10} (a - b) - lo g_{10} (3)

lo g_{10} (\frac{a - b}{3})

Solution steps

lo g_{10} (a - b) - lo g_{10} (3)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (a - b) - lo g_{10} (3) = lo g_{10} (\frac{a - b}{3})

= lo g_{10} (\frac{a - b}{3})

ln (x^{e} e^{x})

ln ∣ x ∣ - 2 ln ∣ x + 1 ∣ + ln ∣ x - 2 ∣ + C

lo g_{3} (\frac{81}{y})

2 ln (3) - 2 ln (2)

lo g_{2} (\frac{8 X ^{3}}{2 Y})

What is log_{10}(a-b)-log_{10}(3) ?
The solution to log_{10}(a-b)-log_{10}(3) is log_{10}((a-b)/3)