What is (2/3)log_{10}(E/(0.7)) ?

The solution to (2/3)log_{10}(E/(0.7)) is (2+2log_{10}(E)-2log_{10}(7))/3

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simplify (2/3)log_{10}(E/(0.7))

simplify

(\frac{2}{3}) lo g_{10} (\frac{E}{0.7})

\frac{2 + 2 lo g _{10} ( E ) - 2 lo g _{10} ( 7 )}{3}

Solution steps

(\frac{2}{3}) lo g_{10} (\frac{E}{0.7})

Apply rule:

(a) = a

(\frac{2}{3}) = \frac{2}{3}

= \frac{2}{3} lo g_{10} (\frac{E}{0.7})

Simplify

lo g_{10} (\frac{E}{0.7}) : 1 + lo g_{10} (E) - lo g_{10} (7)

= \frac{2}{3} (1 + lo g_{10} (E) - lo g_{10} (7))

Expand

\frac{2}{3} (1 + lo g_{10} (E) - lo g_{10} (7)) : \frac{2 + 2 lo g _{10} ( E )}{3} - \frac{2}{3} lo g_{10} (7)

= \frac{2 + 2 lo g _{10} ( E )}{3} - \frac{2}{3} lo g_{10} (7)

Simplify

\frac{2 + 2 lo g _{10} ( E )}{3} - \frac{2}{3} lo g_{10} (7) : \frac{2 + 2 lo g _{10} ( E ) - 2 lo g _{10} ( 7 )}{3}

= \frac{2 + 2 lo g _{10} ( E ) - 2 lo g _{10} ( 7 )}{3}

ln (5) + ln (x) + ln (y)

ln (8) - ln (3)

- lo g_{10} (1.6 \cdot 1 0^{- 7})

5 lo g_{10} (x) + 7 lo g_{10} (y)

lo g_{10} (\frac{6 x}{y})

What is (2/3)log_{10}(E/(0.7)) ?
The solution to (2/3)log_{10}(E/(0.7)) is (2+2log_{10}(E)-2log_{10}(7))/3