What is log_{a}(b)-log_{a}(c) ?

The solution to log_{a}(b)-log_{a}(c) is log_{a}(b/c)

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simplify log_{a}(b)-log_{a}(c)

simplify

lo g_{a} (b) - lo g_{a} (c)

lo g_{a} (\frac{b}{c})

Solution steps

lo g_{a} (b) - lo g_{a} (c)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{a} (b) - lo g_{a} (c) = lo g_{a} (\frac{b}{c})

= lo g_{a} (\frac{b}{c})

2 lo g_{\frac{5}{4}} (2)

lo g_{b} (x^{3}) + lo g_{b} (y)

2 lo g_{8} (x) + 4 lo g_{8} (y)

lo g_{10} (x^{2} - x - 12) - lo g_{10} (x^{2} - 7 x + 12)

lo g_{4} (x) - lo g_{4} (7 y)

What is log_{a}(b)-log_{a}(c) ?
The solution to log_{a}(b)-log_{a}(c) is log_{a}(b/c)