What is 3log_{10}(a)-log_{10}(b) ?

The solution to 3log_{10}(a)-log_{10}(b) is log_{10}((a^3)/b)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 3log_{10}(a)-log_{10}(b)

simplify

3 lo g_{10} (a) - lo g_{10} (b)

lo g_{10} (\frac{a ^{3}}{b})

Solution steps

3 lo g_{10} (a) - lo g_{10} (b)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{10} (a) = lo g_{10} (a^{3})

= lo g_{10} (a^{3}) - lo g_{10} (b)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (a^{3}) - lo g_{10} (b) = lo g_{10} (\frac{a ^{3}}{b})

= lo g_{10} (\frac{a ^{3}}{b})

ln ∣ sin (x) ∣ + ln ∣ sec (x) ∣

lo g_{10} (n lo g_{10} (n))

lo g_{10} (\frac{y ^{3}}{z})

lo g_{10} (48) + lo g_{10} (6) - lo g_{10} (108)

lo g_{7} (3 x + 1) - 2 lo g_{7} (1 + x)

What is 3log_{10}(a)-log_{10}(b) ?
The solution to 3log_{10}(a)-log_{10}(b) is log_{10}((a^3)/b)