What is 10log_{10}(1.6*10^{-5})+120 ?

The solution to 10log_{10}(1.6*10^{-5})+120 is 40log_{10}(2)+60

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simplify 10log_{10}(1.6*10^{-5})+120

simplify

10 lo g_{10} (1.6 \cdot 1 0^{- 5}) + 120

40 lo g_{10} (2) + 60

Decimal Notation

72.04119 \dots

Solution steps

10 lo g_{10} (1.6 \cdot 1 0^{- 5}) + 120

10 lo g_{10} (1.6 \cdot 1 0^{- 5}) = 40 lo g_{10} (2) - 60

= 40 lo g_{10} (2) - 60 + 120

Add the numbers:

- 60 + 120 = 60

= 40 lo g_{10} (2) + 60

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What is 10log_{10}(1.6*10^{-5})+120 ?
The solution to 10log_{10}(1.6*10^{-5})+120 is 40log_{10}(2)+60