What is log_{10}(d)+8log_{10}(q) ?

The solution to log_{10}(d)+8log_{10}(q) is log_{10}(dq^8)

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simplify log_{10}(d)+8log_{10}(q)

simplify

lo g_{10} (d) + 8 lo g_{10} (q)

lo g_{10} (d q^{8})

Solution steps

lo g_{10} (d) + 8 lo g_{10} (q)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

8 lo g_{10} (q) = lo g_{10} (q^{8})

= lo g_{10} (d) + lo g_{10} (q^{8})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (d) + lo g_{10} (q^{8}) = lo g_{10} (d q^{8})

= lo g_{10} (d q^{8})

lo g_{2} (\frac{32}{x - 1})

ln (e^{- 3 x} 2 x - 5) - ln ((6 - 5 x)^{4})

ln (\frac{9}{x ^{2} + 8})

\frac{lo g _{10} ( x + h ) - lo g _{10} ( x )}{h}

lo g_{4} (16 k^{8} x)

What is log_{10}(d)+8log_{10}(q) ?
The solution to log_{10}(d)+8log_{10}(q) is log_{10}(dq^8)