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Popular >

simplify ln|y|-ln|y-1|

Solution

simplify

ln ∣ y ∣ - ln ∣ y - 1 ∣

Solution

ln (\frac{∣ y ∣}{∣ y - 1 ∣})

Solution steps

ln ∣ y ∣ - ln ∣ y - 1 ∣

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ y ∣ - ln ∣ y - 1 ∣ = ln (\frac{∣ y ∣}{∣ y - 1 ∣})

= ln (\frac{∣ y ∣}{∣ y - 1 ∣})

Popular Examples

simplify-0.2*log_{2}(0.2)-0.8*log_{2}(0.8)simplify

- 0.2 \cdot lo g_{2} (0.2) - 0.8 \cdot lo g_{2} (0.8)

simplify ln(k/(2k))simplify

ln (\frac{k}{2 k})

simplify log_{2}(10x)simplify

lo g_{2} (10 x)

simplify 1/3 log_{c}(x)+5log_{c}(y)-4log_{c}(x)simplify

\frac{1}{3} lo g_{c} (x) + 5 lo g_{c} (y) - 4 lo g_{c} (x)

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\frac{1}{2} lo g_{2} (x) - 2 lo g_{2} (y) + lo g_{2} (z)

Frequently Asked Questions (FAQ)

What is ln|y|-ln|y-1| ?
The solution to ln|y|-ln|y-1| is ln((|y|)/(|y-1|))