What is (v-ln(y)+ln(vy))/(v^2) ?

The solution to (v-ln(y)+ln(vy))/(v^2) is (v+ln(v))/(v^2)

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simplify (v-ln(y)+ln(vy))/(v^2)

simplify

\frac{v - ln ( y ) + ln ( v y )}{v ^{2}}

\frac{v + ln ( v )}{v ^{2}}

Solution steps

\frac{v - ln ( y ) + ln ( v y )}{v ^{2}}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (v y) - ln (y) = ln (\frac{v y}{y})

= \frac{v + ln ( \frac{v y}{y} )}{v ^{2}}

Cancel the common factor:

y

= \frac{v + ln ( v )}{v ^{2}}

lo g_{3} (7) + lo g_{3} (2)

lo g_{10} (z y^{7})

lo g_{3} (\frac{y}{27})

lo g_{6} (\frac{q}{12})

lo g_{e} (3 e)

What is (v-ln(y)+ln(vy))/(v^2) ?
The solution to (v-ln(y)+ln(vy))/(v^2) is (v+ln(v))/(v^2)