What is log_{4}(13b^2c) ?

The solution to log_{4}(13b^2c) is log_{4}(13)+log_{2}(b)+log_{4}(c)

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simplify log_{4}(13b^2c)

simplify

lo g_{4} (13 b^{2} c)

lo g_{4} (13) + lo g_{2} (b) + lo g_{4} (c)

Solution steps

lo g_{4} (13 b^{2} c)

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{4} (13 b^{2} c) = lo g_{4} (13) + lo g_{4} (b^{2}) + lo g_{4} (c)

= lo g_{4} (13) + lo g_{4} (b^{2}) + lo g_{4} (c)

Simplify

lo g_{4} (b^{2}) : lo g_{2} (b)

= lo g_{4} (13) + lo g_{2} (b) + lo g_{4} (c)

ln (2 \cdot 3)

ln (x^{2} - 5 x + 6) - ln (x^{2} - 4) + ln (x + 2)

lo g_{2} (9) - lo g_{2} (y) + \frac{1}{2} lo g_{2} (x) - lo g_{2} (3)

3 ln (x) - \frac{3}{2} ln (y) + 4 ln (z)

What is log_{4}(13b^2c) ?
The solution to log_{4}(13b^2c) is log_{4}(13)+log_{2}(b)+log_{4}(c)