What is 2log_{10}(ab) ?

The solution to 2log_{10}(ab) is 2log_{10}(a)+2log_{10}(b)

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simplify 2log_{10}(ab)

simplify

2 lo g_{10} (ab)

2 lo g_{10} (a) + 2 lo g_{10} (b)

Solution steps

2 lo g_{10} (ab)

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{10} (ab) = lo g_{10} (a) + lo g_{10} (b)

= 2 (lo g_{10} (a) + lo g_{10} (b))

Apply the distributive law:

a (b + c) = ab + a c

2 (lo g_{10} (a) + lo g_{10} (b)) = 2 lo g_{10} (a) + 2 lo g_{10} (b)

= 2 lo g_{10} (a) + 2 lo g_{10} (b)

lo g_{3} (8) - lo g_{3} (7)

2 lo g_{10} (c) - (3 lo g_{10} (a) + lo g_{10} (b))

10 lo g_{10} (1 0^{12} I)

lo g_{99} (\frac{9}{23}) + lo g_{99} (\frac{23}{9})

ln (\frac{x}{x + 6})

What is 2log_{10}(ab) ?
The solution to 2log_{10}(ab) is 2log_{10}(a)+2log_{10}(b)