What is 4log_{10}(y)-log_{10}(x) ?

The solution to 4log_{10}(y)-log_{10}(x) is log_{10}((y^4)/x)

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simplify 4log_{10}(y)-log_{10}(x)

simplify

4 lo g_{10} (y) - lo g_{10} (x)

lo g_{10} (\frac{y ^{4}}{x})

Solution steps

4 lo g_{10} (y) - lo g_{10} (x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{10} (y) = lo g_{10} (y^{4})

= lo g_{10} (y^{4}) - lo g_{10} (x)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (y^{4}) - lo g_{10} (x) = lo g_{10} (\frac{y ^{4}}{x})

= lo g_{10} (\frac{y ^{4}}{x})

4.74 + lo g_{10} (\frac{3}{2})

lo g_{10} (3 x^{2})

3 lo g_{2} (z) - \frac{1}{2} lo g_{2} (x) + 4 lo g_{2} (w)

7 ln (\frac{6}{5})

ln (31 x^{5} y)

What is 4log_{10}(y)-log_{10}(x) ?
The solution to 4log_{10}(y)-log_{10}(x) is log_{10}((y^4)/x)