What are the solutions to the equation 54+16x-x^2=0 ?

The solutions to the equation 54+16x-x^2=0 are x=8-sqrt(118),x=8+sqrt(118)

Find the zeros of 54+16x-x^2=0

The zeros of 54+16x-x^2=0 are x=8-sqrt(118),x=8+sqrt(118)

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54 + 16 x - x^{2} = 0

x = 8 - 118, x = 8 + 118

Decimal Notation

x = - 2.86278 \dots, x = 18.86278 \dots

Solution steps

54 + 16 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 16 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 1 ) \cdot 54}{2 ( - 1 )}

1 6^{2} - 4 (- 1) \cdot 54 = 2118

x_{1, 2} = \frac{- 16 \pm 2 118}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 16 + 2 118}{2 ( - 1 )}, x_{2} = \frac{- 16 - 2 118}{2 ( - 1 )}

x = \frac{- 16 + 2 118}{2 ( - 1 )} : 8 - 118

x = \frac{- 16 - 2 118}{2 ( - 1 )} : 8 + 118

The solutions to the quadratic equation are:

x = 8 - 118, x = 8 + 118

x + 2 < 4 x - 7

\frac{435}{100} + \frac{5}{2}

a^{2} + 9 - 6 a

\frac{∣ x - 5 ∣}{x} + \frac{x - 2}{x + 1} \leq 0

\frac{4}{x} - 3 > \frac{2 x}{x} - 7

What are the solutions to the equation 54+16x-x^2=0 ?
The solutions to the equation 54+16x-x^2=0 are x=8-sqrt(118),x=8+sqrt(118)
Find the zeros of 54+16x-x^2=0
The zeros of 54+16x-x^2=0 are x=8-sqrt(118),x=8+sqrt(118)