What is ln((\sqrt[3]{xy})/(wz^2)) ?

The solution to ln((\sqrt[3]{xy})/(wz^2)) is ln(\sqrt[3]{xy})-ln(w)-2ln(z)

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simplify ln((\sqrt[3]{xy})/(wz^2))

simplify

Solution steps

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (w z^{2}) = ln (w) + ln (z^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (z^{2}) = 2 ln (z)

- (ln (w) + 2 ln (z)) : - ln (w) - 2 ln (z)

lo g_{a} (\frac{x}{y ^{8} z})

2 lo g_{10} (a) + 4 lo g_{10} (b) - 9 lo g_{10} (c)

\frac{1}{2} [5 ln (x + 4) + ln (x) - ln (x^{5} - 3)]

ln (24) - ln (6)

\frac{1}{2} (lo g_{9} (a) + lo g_{9} (b))

What is ln((\sqrt[3]{xy})/(wz^2)) ?
The solution to ln((\sqrt[3]{xy})/(wz^2)) is ln(\sqrt[3]{xy})-ln(w)-2ln(z)