What is 4[log_{2}(k)-log_{2}(k-t)] ?

The solution to 4[log_{2}(k)-log_{2}(k-t)] is 4log_{2}(k/(k-t))

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simplify 4[log_{2}(k)-log_{2}(k-t)]

simplify

4 [lo g_{2} (k) - lo g_{2} (k - t)]

4 lo g_{2} (\frac{k}{k - t})

Solution steps

4 (lo g_{2} (k) - lo g_{2} (k - t))

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (k) - lo g_{2} (k - t) = lo g_{2} (\frac{k}{k - t})

= 4 lo g_{2} (\frac{k}{k - t})

ln (28) 0.125 + ln (\frac{3}{5}) 0.6 - 49 ln (7 e^{3})

lo g_{4} (\frac{x - 2}{x ^{5}})

lo g_{10} (\frac{1 0 ^{2} \cdot 1000}{x ^{3} \cdot y ^{- 2}})

lo g_{10} (\frac{10}{a ^{2} + b ^{2}})

5 lo g_{2} (x) + \frac{3}{4} lo g_{2} (y) - lo g_{2} (z)

What is 4[log_{2}(k)-log_{2}(k-t)] ?
The solution to 4[log_{2}(k)-log_{2}(k-t)] is 4log_{2}(k/(k-t))