What is log_{2}(2x+1)-log_{2}(x-3) ?

The solution to log_{2}(2x+1)-log_{2}(x-3) is log_{2}((2x+1)/(x-3))

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simplify log_{2}(2x+1)-log_{2}(x-3)

simplify

lo g_{2} (2 x + 1) - lo g_{2} (x - 3)

lo g_{2} (\frac{2 x + 1}{x - 3})

Solution steps

lo g_{2} (2 x + 1) - lo g_{2} (x - 3)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (2 x + 1) - lo g_{2} (x - 3) = lo g_{2} (\frac{2 x + 1}{x - 3})

= lo g_{2} (\frac{2 x + 1}{x - 3})

lo g_{10} (\frac{\frac{1}{100} ( x ^{2} + 1 )}{x ^{4} ( x + 1 )})

2 ln (x) + 5 ln (y) - 3 ln (z)

4 ln (3 cos (x))

lo g_{10} (y z^{12})

- lo g_{10} (7.5 \cdot 1 0^{- 4})

What is log_{2}(2x+1)-log_{2}(x-3) ?
The solution to log_{2}(2x+1)-log_{2}(x-3) is log_{2}((2x+1)/(x-3))